Question

An aeroplane leaves an airport and files due south at
a speed of 2000 km per hour. At the same time
another aeroplane leaves the same airport and flies
due east at a speed of 2400 km per hour. How far
apart will be the two planes after 2and half
hours?​

Answer 1

ANSWER:

THE FIRST AIRPLANE WOULD BE 5000 KM FAR FROM THE AIRPORT IT DEPARTURED. WHILE THE SECOND AIRPLANE WOULD BE 6000 KM FAR FROM THE AIRPORT IT DEPARTURED.

Answer 2

Answer:

7810.24 km.

Step-by-step explanation:

Time taken by the plane is 2(1/2) or 2.5 hrs and the speed separately is for south flying aeroplane is 2000 km/hr and for the east flying aeroplane is 2400 km/hr.

So, distance traveled by the south flying aeroplane is 2000*2.5 = 5000 km and for the east flying aeroplane will be 2400*2.5 = 6000km.

Hence, now applying the Pythagoras theorem we will get the required distance that the two planes are separated.

so, the distance d^2 = 5000^2 + 6000^2 = 25000000 +  36000000 which will be equal to d^2 = 61000000 so, d= 7810.24 km.