Question

An aeroplane leaves an airport and flies due north at a speed of 1000 km per hour At the
Same time, another aeroplane leaves the same airport and flies due west at a speed of
1200 km per hour. How par apart will be the two planes after 1 1/2 hours.?​

Answer 1

Answer:

Step-by-step explanation:

Distance covered by the first plane in 1.5 hours = 1500 km 

Distance covered by the second plane in 1.5 hours = 1800 km

The position of the two planes after 1.5 hour journey can be shown by a right triangle and we need to find the hypotenuse to know the aerial distance between them.

Here; h = ? p = 1800 km and b = 1500 km

From Pythagoras theorem;

h2 = p2 + b2Or, h2 = 18002 + 15002= 3240000 + 2250000 = 5490000Or, h = 300√61 km

Answer 2

Step-by-step explanation:

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