Question

An aeroplane moves 400 m towards north 300 m towards west and then 1200 m
vertically upwards. Then its displacement from the initial position is
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Answer 1

Explanation:

it's displacement

= \sqrt{(\sqrt{400 {}^{2} + 300 {}^{2} } ) {}^{2} + 1200 {}^{2} } m \\ = \sqrt{1690000} \\ = 1300m