An aeroplane takes off at an angle of 30degrees to the horizontal. If the component of its velocity along the horizontal is 250km/hr what if the actual velocity. Find also is vertical component.
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i think it is the same question which is already answered:
let the velocity of the plane be V m/s
horizontal component of velocity =
V cos 30°= 200
v x √3/2 = 200
v = 400/√3
=231 km/hr
vertical component of velocity is
V sin 30 = v/2=115.47 km/h
let the velocity of the plane be V m/s
horizontal component of velocity =
V cos 30°= 200
v x √3/2 = 200
v = 400/√3
=231 km/hr
vertical component of velocity is
V sin 30 = v/2=115.47 km/h
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