An aeroplane takes off at an angle of 45 to the horizontal. If the vertical component of its velocity is 300 kmph, calculate its actual velocity. What is the horizontal component of velocity?
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let v be velocity
it is resolved along horizontal and vertical components as v cos 45 and v sin 45
v sin 45=300 kmph
v=300*√2 kmph
and v cos 45=300*√2/√2=300 kmph
it is resolved along horizontal and vertical components as v cos 45 and v sin 45
v sin 45=300 kmph
v=300*√2 kmph
and v cos 45=300*√2/√2=300 kmph
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