an aeroplane taking off from a field has a run of 500 m what is its acceleration and takeoff speed if its leaves at the ground after 10 seconds after the start
Answers
Answered by
3
So according to the condition of the question
s=500
u=0
t=10
so by formula
s=ut+1/2at^2
500=0+1/2 a 10*10
500=5*10*a
a=500/50
a=10 m/s^2
now by another formula
v=u+at
v=0+1(10)
v=100 m/s
s=500
u=0
t=10
so by formula
s=ut+1/2at^2
500=0+1/2 a 10*10
500=5*10*a
a=500/50
a=10 m/s^2
now by another formula
v=u+at
v=0+1(10)
v=100 m/s
Answered by
0
Answer:Lewis structure.
Lowest energy structure is the one with a factor based on a pure covalent bond between the two
atoms.
Explanation:Formal charges help in the selection of the lowest energy structure from the number of possible
Lewis structure.
Lewis structure.
Lowest energy structure is the one with a factor based on a pure covalent bond between the two
atoms.
Explanation:Formal charges help in the selection of the lowest energy structure from the number of possible
Lewis structure.
Lowest energy structure is the one with a factor based on a pure covalent bond between the two
atoms.
Lowest energy structure is the one with a factor based on a pure covalent bond between the two
atoms.
Explanation:
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