Question

An aeroplane touches down at 225 km h-1 and stops after 2 minutes find the accelaration

Answer 1

Answer:

-0.5220833 m/s²

Explanation:

Given :

• Initial velocity = u = 225 km/hr

• Final velocity = v = 0 m/s

• Time taken = t = 2 minutes = 120 seconds

To find :

• Acceleration of the aeroplane

Converting 225 km/hr to m/s :

225 × 5/18 = 62.5 m/s

Using the first equation of motion :

V=u+at

0=62.5+a×120

-62.5 = 120 a

a = - 62.5/120

a = - 0.5208333 m/s²

The acceleration of the aeroplane is equal to -0.520833 m/s²

More :

• Second equation of motion = s=ut+½at²

• Third equation of motion = v²-u²=2as

Answer 2

Explanation:

Distance=225 km

Time=2minutes

=120 second

speed in m/s=225×5/18

=62.5 m/s

v=u+at

0=62.5+a×120

-62.5=120a

a=-62.5/120

=-0.520...