Question

An aeroplane ,when 3000m high vertically above another plane at an instant when the angle of elevation of two aeroplanes from the same point on the ground are 60degre and 45degre respectivelly . Find the vertical distance between the two planes.

Answer 1

Answer:

Step-by-step explanation:

tan60= AC/BC

√3=3000/b

b√3=3000

b=3000/√3

b=1000√3

BC=1000√3

Now tan45°=DC/BC

1=h/1000√3

h=1000√3

x=AC-DC

x=3000-1000√3

x=1000√3(√3-1)