An aeroplane would take one hour less for a journey of 1200km if it increases its usual speed by 100km/hr.What is its usual speed?
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let hours taken x hours
so speed s=1200/x
speed increases by 100kmph (s+100)
time taken (x-1)hour
distance is same
therefore sx=(s+100)×(x-1)
by solving from above equations we can get answer matehi
so speed s=1200/x
speed increases by 100kmph (s+100)
time taken (x-1)hour
distance is same
therefore sx=(s+100)×(x-1)
by solving from above equations we can get answer matehi
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