An agricultural field is in the form of a rectangle with length 20 m and width 14 mA
6 m long. 3 m wide and 5.5 m deep is dug in a corner of the field and the earth tak
out of it is spread uniformly over the remaining area of the field. What is the extent
which the level of the field is raised? Round of your answers to 2 places of decimal
Three cubes of side 5 cm are joined from end to end. What is the surface area of the
resulting cuboid?
Yourself...
and you know about Mensuration before starting this chapter? Tick
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Answers
Answer:
1) An agricultural field is in the form of a rectangle with length 20 m and width 14 mA
6 m long. 3 m wide and 5.5 m deep is dug in a corner of the field and the earth tak
out of it is spread uniformly over the remaining area of the field. What is the extent
which the level of the field is raised?
Answer
Length of field = L = 20 m Length of hole = l = 6 m
Width of field = B = 14 m Width of hole = b = 3 m
Rise in height = H Depth of hole = h =5.5 m
Area left after the hole is dug = Area of field - Area of hole
Area left after the hole is dug = L*B - l*b
Area left after the hole is dug = 20 x 14 - 6 x 3
Area left after the hole is dug = 280 - 18
Area left after the hole is dug = 262 m²
so
Area left after the hole is dug x Rise in height = Volume of Earth dug
262 x H = 6 x 3 x 5.5
H = 0.37 m
2) Three cubes of side 5 cm are joined from end to end. What is the surface area of the resulting cuboid?
Answer
Length of resulting cuboid(l) = 3*s = 15 cm
Breadth of resulting cuboid(b) = s = 5 cm
Height of resulting cuboid(h) = s = 5 cm
Surface area = 2(lb + bh + hl)
Surface area = 2(75 + 25 + 75)
Surface area = 2(175)
Surface area = 350 cm²
Answer:
35 Cm
Step-by-step explanation: figure attached.
