Question

Solution of question nu.15

Answer 1

Answer:

answer is in the above attachment

Answer 2

Let the two natural numbers be x and y.

Let the two natural numbers be x and y.A/q

Let the two natural numbers be x and y.A/qy - x = 5

Let the two natural numbers be x and y.A/qy - x = 51/x - 1/y = 5/14

Let the two natural numbers be x and y.A/qy - x = 51/x - 1/y = 5/14From 1.

Let the two natural numbers be x and y.A/qy - x = 51/x - 1/y = 5/14From 1.y = x + 5

Let the two natural numbers be x and y.A/qy - x = 51/x - 1/y = 5/14From 1.y = x + 5Putting the value of y in eqn. 2

Let the two natural numbers be x and y.A/qy - x = 51/x - 1/y = 5/14From 1.y = x + 5Putting the value of y in eqn. 21/x - 1/(x+5) = 5/14

Let the two natural numbers be x and y.A/qy - x = 51/x - 1/y = 5/14From 1.y = x + 5Putting the value of y in eqn. 21/x - 1/(x+5) = 5/14x+5-x / x(x+5) = 5/14

Let the two natural numbers be x and y.A/qy - x = 51/x - 1/y = 5/14From 1.y = x + 5Putting the value of y in eqn. 21/x - 1/(x+5) = 5/14x+5-x / x(x+5) = 5/145 / x2 + 5x = 5/14

Let the two natural numbers be x and y.A/qy - x = 51/x - 1/y = 5/14From 1.y = x + 5Putting the value of y in eqn. 21/x - 1/(x+5) = 5/14x+5-x / x(x+5) = 5/145 / x2 + 5x = 5/14x2 + 5x - 14 = 0

Let the two natural numbers be x and y.A/qy - x = 51/x - 1/y = 5/14From 1.y = x + 5Putting the value of y in eqn. 21/x - 1/(x+5) = 5/14x+5-x / x(x+5) = 5/145 / x2 + 5x = 5/14x2 + 5x - 14 = 0x2 + (7-2)x - 14 = 0

Let the two natural numbers be x and y.A/qy - x = 51/x - 1/y = 5/14From 1.y = x + 5Putting the value of y in eqn. 21/x - 1/(x+5) = 5/14x+5-x / x(x+5) = 5/145 / x2 + 5x = 5/14x2 + 5x - 14 = 0x2 + (7-2)x - 14 = 0x2 + 7x - 2x - 14 = 0

Let the two natural numbers be x and y.A/qy - x = 51/x - 1/y = 5/14From 1.y = x + 5Putting the value of y in eqn. 21/x - 1/(x+5) = 5/14x+5-x / x(x+5) = 5/145 / x2 + 5x = 5/14x2 + 5x - 14 = 0x2 + (7-2)x - 14 = 0x2 + 7x - 2x - 14 = 0x(x+7) - 2(x+7) = 0

Let the two natural numbers be x and y.A/qy - x = 51/x - 1/y = 5/14From 1.y = x + 5Putting the value of y in eqn. 21/x - 1/(x+5) = 5/14x+5-x / x(x+5) = 5/145 / x2 + 5x = 5/14x2 + 5x - 14 = 0x2 + (7-2)x - 14 = 0x2 + 7x - 2x - 14 = 0x(x+7) - 2(x+7) = 0(x+7) (x-2) = 0

Let the two natural numbers be x and y.A/qy - x = 51/x - 1/y = 5/14From 1.y = x + 5Putting the value of y in eqn. 21/x - 1/(x+5) = 5/14x+5-x / x(x+5) = 5/145 / x2 + 5x = 5/14x2 + 5x - 14 = 0x2 + (7-2)x - 14 = 0x2 + 7x - 2x - 14 = 0x(x+7) - 2(x+7) = 0(x+7) (x-2) = 0Either

Let the two natural numbers be x and y.A/qy - x = 51/x - 1/y = 5/14From 1.y = x + 5Putting the value of y in eqn. 21/x - 1/(x+5) = 5/14x+5-x / x(x+5) = 5/145 / x2 + 5x = 5/14x2 + 5x - 14 = 0x2 + (7-2)x - 14 = 0x2 + 7x - 2x - 14 = 0x(x+7) - 2(x+7) = 0(x+7) (x-2) = 0Eitherx+7 = 0

Let the two natural numbers be x and y.A/qy - x = 51/x - 1/y = 5/14From 1.y = x + 5Putting the value of y in eqn. 21/x - 1/(x+5) = 5/14x+5-x / x(x+5) = 5/145 / x2 + 5x = 5/14x2 + 5x - 14 = 0x2 + (7-2)x - 14 = 0x2 + 7x - 2x - 14 = 0x(x+7) - 2(x+7) = 0(x+7) (x-2) = 0Eitherx+7 = 0x = -7

Let the two natural numbers be x and y.A/qy - x = 51/x - 1/y = 5/14From 1.y = x + 5Putting the value of y in eqn. 21/x - 1/(x+5) = 5/14x+5-x / x(x+5) = 5/145 / x2 + 5x = 5/14x2 + 5x - 14 = 0x2 + (7-2)x - 14 = 0x2 + 7x - 2x - 14 = 0x(x+7) - 2(x+7) = 0(x+7) (x-2) = 0Eitherx+7 = 0x = -7Not acceptable because -7 is not a natural number.

Let the two natural numbers be x and y.A/qy - x = 51/x - 1/y = 5/14From 1.y = x + 5Putting the value of y in eqn. 21/x - 1/(x+5) = 5/14x+5-x / x(x+5) = 5/145 / x2 + 5x = 5/14x2 + 5x - 14 = 0x2 + (7-2)x - 14 = 0x2 + 7x - 2x - 14 = 0x(x+7) - 2(x+7) = 0(x+7) (x-2) = 0Eitherx+7 = 0x = -7Not acceptable because -7 is not a natural number.Or,

Let the two natural numbers be x and y.A/qy - x = 51/x - 1/y = 5/14From 1.y = x + 5Putting the value of y in eqn. 21/x - 1/(x+5) = 5/14x+5-x / x(x+5) = 5/145 / x2 + 5x = 5/14x2 + 5x - 14 = 0x2 + (7-2)x - 14 = 0x2 + 7x - 2x - 14 = 0x(x+7) - 2(x+7) = 0(x+7) (x-2) = 0Eitherx+7 = 0x = -7Not acceptable because -7 is not a natural number.Or,x - 2 = 0

Let the two natural numbers be x and y.A/qy - x = 51/x - 1/y = 5/14From 1.y = x + 5Putting the value of y in eqn. 21/x - 1/(x+5) = 5/14x+5-x / x(x+5) = 5/145 / x2 + 5x = 5/14x2 + 5x - 14 = 0x2 + (7-2)x - 14 = 0x2 + 7x - 2x - 14 = 0x(x+7) - 2(x+7) = 0(x+7) (x-2) = 0Eitherx+7 = 0x = -7Not acceptable because -7 is not a natural number.Or,x - 2 = 0x = 2

Let the two natural numbers be x and y.A/qy - x = 51/x - 1/y = 5/14From 1.y = x + 5Putting the value of y in eqn. 21/x - 1/(x+5) = 5/14x+5-x / x(x+5) = 5/145 / x2 + 5x = 5/14x2 + 5x - 14 = 0x2 + (7-2)x - 14 = 0x2 + 7x - 2x - 14 = 0x(x+7) - 2(x+7) = 0(x+7) (x-2) = 0Eitherx+7 = 0x = -7Not acceptable because -7 is not a natural number.Or,x - 2 = 0x = 2so,First number = 2

2 + 5=7

2 + 5=7HOPE IT HELPS U N PLZ MARK ME AS BRAINLIEST

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