Question

an air column in a pipe, which is closed at one end , will be in resonance with a vibrating tuning fork of frequency 264 hz if the length of the column in cm is : ( velocity of sound = 330m/s)

Answer 1

Natural frequencies of a pipe of length ll, closed at one end, are given by, ν=nv/(4l)ν=nv/(4l), where v=330m/sv=330m/s is the speed of sound and nn is an odd integer. Thus, the possible length of pipe (closed at one end) that can resonate with a tuning fork of frequency ν=264Hzν=264Hz are,
ln=nv4ν=n(330)4(264)=0.3125nm,
ln=nv4ν=n(330)4(264)=0.3125nm,
which gives l1=31.25cml1=31.25cm, l3=93.75cml3=93.75cm, l5=156.25cml5=156.25cm

Answer 2

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