Physics, asked by asiyaar, 7 months ago

An air core capacitor has a value 2uF. Now a dielectric of constant 4 and thickness equal to half the separation between the plates is filled in the region between the plates. The new capacitance value is ​

Answers

Answered by NishantRaj7
3

Answer:

cortisol keep

 { {1 \frac{ \frac{ {023 \times  -  \div  \div 0y1212.0 {1.23 \frac{ { \\  \\  \\  \\  \\ 1x65 \\  \\  \\  \\  \\ 5 { \\  \\  \\ }^{?} }^{?} }{?} }^{?}  \times \frac{?}{?}  \times \frac{?}{?} }^{?} }{?} }{?} }^{?} }^{?}

Gkh

Answered by knjroopa
0

Explanation:

  • So we have a capacitor with spacing.
  • So capacitance C = A Ʃ / d
  •      Now C = AƩo / d
  • Now new capacitance will be
  •            C1 = A (kƩo) / d/2 (k is the directrix constant)
  •              C1 = AƩo / d x 2k
  •              C1 = C x 2 x 4 (since C = AƩo/d) (C is the air permittivity or air has a directrix medium)
  •                C1 = 2µF x 2 x 4
  •           Or C1 = 16 µF
  • So the new capacitance value is 16 µF

Reference link will be

https://brainly.in/question/7225298

Similar questions