An air storage tank whose volume is 110litres contains 2kg of air ar pressure of 15atm.how much air would have to be forced into the tank to increase the pressure to 18 atm, assuming no change in temperature?
Answers
Answer:
We need to use the ideal gas law PV = nRT. We have two conditions, which I'll note with the subscripts 1 and 2, for the initial and final conditions.
The values for each are:
P1 = 15atm
V1 = 110L
n1 = 2kg
T1 = constant
P2 = 18atm
V2 = 110L
n2 = X
T2 = constant
The values for each are:
P1 =
P1V1 = n1RT1 and P2V2 = n2RT2
Note that neither the volume nor the temperature change, so V1 = V2 and T1 = T2.
We can divide one equation by the other, and cancel the values that do not change:
(P1V1)/(P2V2) = (n1RT1)/(n2RT2)
Cancel the volumes and temperatures, since they do not change.
(P1)/(P2) = (n1)/(n2)
I'll invert this to get the ratio n2/n1
n2/n1 = P2/P1
n2/n1 = 18atm/15atm
n2/n1 = 1.2
2kg * 1.2 = 2.4kg air needed to increase pressure to 18 atm.
Note that n1 and n2 should both be in units of moles for the ideal gas law, but we are looking at the ratio of n2 to n1 and all gases have a value of 22.4 L/mole at STP. So the ratio of n1/n2 should also be the ratio of those gases in mass, since we aren't changing the composition ("air").
Explanation:
thank you
Answer:0.4Kg
Explanation:
An air storage tank whose volume is 110litres contains 2Kg of air at a pressure of 15atm.How much air would have to force into the tank to increased the pressure to 18atm,assuming no change in temperature