Physics, asked by rathorejia1, 3 days ago

An air storage tank whose volume is 110litres contains 2kg of air ar pressure of 15atm.how much air would have to be forced into the tank to increase the pressure to 18 atm, assuming no change in temperature?​

Answers

Answered by mufiahmotors
4

Answer:

We need to use the ideal gas law PV = nRT.  We have two conditions, which I'll note with the subscripts 1 and 2, for the initial and final conditions.

The values for each are:

P1 = 15atm

V1 =  110L

n1 = 2kg

T1 = constant

P2 = 18atm

V2 =  110L

n2 =  X

T2 = constant

The values for each are:

P1 =  

P1V1 = n1RT1 and P2V2 = n2RT2

Note that neither the volume nor the temperature change, so V1 = V2 and T1 = T2.

We can divide one equation by the other, and cancel the values that do not change:

(P1V1)/(P2V2) = (n1RT1)/(n2RT2)

Cancel the volumes and temperatures, since they do not change.

(P1)/(P2) = (n1)/(n2)

I'll invert this to get the ratio n2/n1

n2/n1 = P2/P1

n2/n1 = 18atm/15atm

n2/n1 = 1.2

2kg * 1.2 = 2.4kg air needed to increase pressure to 18 atm.

Note that n1 and n2 should both be in units of moles for the ideal gas law, but we are looking at the ratio of n2 to n1 and all gases have a value of 22.4 L/mole at STP.  So the ratio of n1/n2 should also be the ratio of those gases in mass, since we aren't changing the composition ("air").

Explanation:

thank you

Answered by Harisraza309
1

Answer:0.4Kg

Explanation:

An air storage tank whose volume is 110litres contains 2Kg of air at a pressure of 15atm.How much air would have to force into the tank to increased the pressure to 18atm,assuming no change in temperature

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