Question

an aircraft accelerates at 2.5m/s^2. It's take off speed is 60 m/s.
a) What length of runway does it need to take off ?
b) how long does it take to reach its take of speed?

Answer 1

Explanation:

v2=u2+2.a.S

S, distance, is the unknown.

S=(v2−u2)/(2.a)

v is 60m/s, u is 0m/s, a is 2.5m/s2

S=(3600–0)/5

S=720m

hope it will help

Answer 2

Answer:

v=a*t

t=60/2.5s

t=24s.

Explanation:

Integration of the formula above, with x=vt gives:

x=1/2at²

x=12∗2.5∗24²m

x=720m.