Question

an aircraft is flying at a height of 150m above the sea level. If the angle of elevation of the aircraft from an observer on the sea surface is 45 degrees.
Find the shortest distance between the observer and the aircraft.

Answer 1

Answer:

Given:

Distance between the foot of the tower and point of observation = 20 m = BC

Angle of elevation of the top of the tower = 60° = θ

And, Height of tower (H) = AB

Now, from fig. ABC

ΔABC is a right angle triangle,