Question

An airplane accelerates down a runway at 3.10 m/s 2  for 34.8 s until is finally lifts off the ground. Determine the final velocity after 34.8 seconds..

Answer 1

Answer:

a= 3.10m/s^2

t=34.8s

u=0m/s (As it is taking off )

v=u+at

v=0+3.10×34.8=107.8m/s

Explanation:

MARK AS BRAINLIEST.