An airplane accelerates down a runway at 3.20 m/sec2 for 32.8 sec until its finally lifts off the ground. Determine the distance traveled before takeoff.
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We know that s=ut+1/2at2 (u=0 because the plane starts moving)
s= 0*32.8+1/2*3.2*32.8^2
s= 1721.3m
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Answered by
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hey mate !! here is ur answer
s = ut + 1/2at^2
0×32.8 + 1/2 ×3.20×32.8×32.8
0 + 1721.344m
1721.344m
hop eit helps u..✌✌
s = ut + 1/2at^2
0×32.8 + 1/2 ×3.20×32.8×32.8
0 + 1721.344m
1721.344m
hop eit helps u..✌✌
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