Question

An airplane flies 2640 miles in 3 hours 40 minutes. What is it’s average speed in miles per hour?

Answer 1

Answer:

In the above question, we are given with the miles covered by the aeroplane and time taken.

GiveN:

• Distance covered = 2640 miles
• Time taken = 3 hours 40 minutes

We have to find average speed of the aeroplane...?

By using the formula for finding average speed:

$\large \boxed{ \rm{Avg. \: speed = \frac{distance}{time} }}$

Now as we can see that the time is to be expressed in hours wholly, let's convert that:

$\rm{\longrightarrow 40 \: minutes = \dfrac{2}{3} hour}$

So, 3 hours 40 minutes can be written as $\rm{\longrightarrow 3 \dfrac{2}{3} hour}$. So, let's find the average speed by plugging the required values:

$\rm{\longrightarrow Avg. \: speed = \dfrac{2640 \: miles}{3 \dfrac{2}{3} \: hour } }$

Simplifying,

$\rm{ \longrightarrow Avg. \: speed = \dfrac{2640 \: miles}{ \dfrac{11}{3} \:hours } }$

This would be equals to,

$\rm{\longrightarrow Avg. \: speed = 720 \: miles \: {hr}^{ - 1}}$

Hence, the Average speed of the aeroplane:

$\large{ \boxed{ \sf{ \red{720 \: miles \: {hr}^{ - 1} }}}}$

And we are done !!

Answer 2

Explanation:

In the above question, we are given with the miles covered by the aeroplane and time taken.

Given:

Distance covered = 2640 miles

Time taken = 3 hours 40 minutes

By using the formula for finding average speed:

$\large \boxed{ \green \rm{Avg. \: speed = \frac{distance}{time} }}$

Now as we can see that the time is to be expressed in hours wholly, let's convert that:

$\rm{\longrightarrow 40 \: minutes = \dfrac{2}{3} hour}$

So, 3 hours 40 minutes can be written as

$\rm{\longrightarrow 3 \dfrac{2}{3} hour}$

So, let's find the average speed by plugging the required values:

$\rm{\longrightarrow Avg. \: speed = \dfrac{2640 \: miles}{3 \dfrac{2}{3} \: hour } }$

Simplifying,

$\rm{ \longrightarrow Avg. \: speed = \dfrac{2640 \: miles}{ \dfrac{11}{3} \:hours } }$

This would be equals to,

$\rm{\longrightarrow Avg. \: speed = 720 \: miles \: {hr}^{ - 1}}$

Hence, the Average speed of the aeroplane:

$\large{ \boxed{ \sf{ {720 \: miles \: {hr}^{ - 1} }}}}$