Question

an airplane is navigating a polygon-shaped course. each turn is labeled with the measure of the external angle at the striped post. what is m<1​

Answer 1

Answer:

100

Step-by-step explanation:

angle 2 is 180-90 =90degree

angle 3 is 180-70 = 110 degree

angle 4 is 180-50= 130 degree

angle 5 is given 110 degree

now sum of all angles is 540 in pentagon

so angle 1 +90+110+130+110=540

angle1+440=540

angle1= 100

Answer 2

Answer: $100^{0}$

Step-by-step explanation:

• let angle 1, 2, 3, 4, and 5 =$A_{1}$,$A_{2} A_{3} A_{4} and A_{5}$ respectively

• firstly we know

            $angle A_{2} =180^{0} -90^{0}$

                          $=90^{0}$

           $angleA_{3} =180^{0} -70^{0}$

                         $=110^{0}$

          $angleA_{4} = 180^{0} -50^{0}$

                        $=130^{0}$

• we know that,

         $angle A_{5} =110^{0}$

• Now sum of all angles is $540^{0}$in pentagon

               $A_{1} +A_{2}+ A_{3} +A_{4} +A_{5} =540^{0}$

       $A_{1} +90^{0}+ 110^{0} +130^{0} +110^{0} =540^{0}$

               $A_{1} +440^{0} =540^{0}$

            ∴ $A_{1} =100^{0}$