Question

An airplane travels 6000 km against the wind in 8 hours and 6720 with the wind in the same amount of time. What is the rate of the plane in still air and what is the rate of the wind?

Answer 1

let speed of wind = y
speed of plane = x
relative speed = x-y [CASE 1 ]
d= s×t
so 8(x-y) = 6000
x-y = 750. (1)

8(x+y) = 6720. [CASE 2]
x+y = 840. (2)

adding 1, 2 equations,
2x = 1590
x= 795 km/h

so speed of plane = 795 km/h
speed of wind = 840 - 795 = 45km/h

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