Question

An aliphatic hydrocarbon consisting of three carbon
atoms are arranged continuously. All the three are sp3
carbons.
If middle carbon is bonded with one vinyl
group, one isopropenyl group and the
tetracovalency of all the carbon atoms
satisfied required number of hydrogens.
Then IUPAC name of resultant compound
could be
3,3,4-trimethyl penta-1,4-diene
2,3,3-Trimethyl penta-1,4-diene
2-vinyl-2-iso propenyl propene
O
3-vinyl-2,3-dimethyl-1-butene​

Answer 1

Answer:

The IUPAC name of the resultant compound is 2,3,3-trimethylpenta-1,4-diene.

Explanation:

The IUPAC naming method is a method used to name organic compounds in chemistry. There are some rules of this naming method.

1. Identify the parent chain, the longest carbon chain.
2. Identify all the substituents (groups attached to the parent chain).
3. Number the carbons of the parent chain in the order that substituents get the lowest number.
4. If the same substituent occurs more than once, then give the position along with the prefixes (di, tri, tetra, etc.)
5. If two or more different substituents are present then name in the alphabetical order (ignore prefixes). The only prefix which can be used is “iso”, such as isopropyl, isobutyl, etc.
6. If chains of equal length are competing for the parent chain, then choose the chain with the greatest number of side chains, whose substituents have the lowest numbers, the greatest number of carbons in the smallest side chain, and the least branched side chains.
7. Cyclic hydrocarbons are designated by the prefix “cyclo” just before the base name.

In the above-mentioned question, two groups, vinyl group(-CH=CH₂) and isopropenyl group(-C(CH₃)=CH₂) are added to the three carbons aliphatic chain. This results in the formation of a resultant compound with the parent chain of five carbons with double bounds at the first and fourth carbon, substituents are three methyl groups, one on position 2 and the other two on position 3. Hence, the IUPAC name is 2,3,3-trimethylpenta-1,4-diene.

#SPJ3