Question

an alkene A undergoes addition with Hbr to giveB When B is heated with sodium in presence of dry Ether give 2 3 dimethylbutane identify a and b​

Answer 1

Answer:

The supplied response may be shown as follows:

A + HBr → B

2,3-Dimethylbutane = B + Sodium + Ether

Explanation:

First, alkyne A reacts with HBr to produce alkyne B. The reaction shown here is an instance of electrophilic addition. The -electron cloud of the alkene is attacked by the electrophilic HBr molecule, forming a carbocation intermediate. Product B is then formed when the bromide ion attacks the carbocation. According to Markovnikov's rule, this reaction occurs when the HBr molecule's hydrogen atom binds to the alkene's carbon atom with the fewest hydrogen atoms linked to it.

Second, B is heated in the presence of sodium and dry ether. We call this particular response the Wurtz reaction. As a reducing agent, sodium metal converts the alkyl halide into the simpler alkane form. 2,3-dimethylbutane results from the reduction of B. By interacting with the alkyl halide, the sodium metal produces alkyl radicals, a free radical mechanism that drives the reaction forward. The final product is formed when these radicals react with one another.

Since A is an alkene, it may be converted into B by addition to HBr. Alkyl halide B may be converted to 2,3-dimethylbutane by reduction with sodium and dry ether. Because moisture may stifle chemical reactions, the Wurtz reaction can only occur under dry ether reaction conditions. Symmetrical alkanes may be synthesized from alkyl halides using this process.

To learn more about Dimethylbutane, click on the link below.

https://brainly.in/question/1532212

To learn more about Sodium, click on the link below.

https://brainly.in/question/54155666

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