Question

An alloy consists of 13 parts of copper, 7 parts of zinc amd 5 parts of nickel. Find the % of copper in the alloy

Answer 1

LET TAKE THE PERCENTAGE OF COPPER BE X.
LETS TAKE THE PERCENTAGE OF ZINC BE Y
THEN PERCENTAGE OF NICKEL BE Z.
SO WE CAN WRITE
X+Y+Z=100
A/Q
13+7+5*(X)=100%
25*(X)=100
THEN X=4%
PERCENTAGE OF COPPER PARTS=13*4=52%

Answer 2

Percentage of Copper = 52%

Total Parts of Alloy = 13+7+5 => 25

% of Copper = $\sf{\dfrac{13}{25}\times 100 = 13\times4=52\%}$

% of Zinc = $\sf{\dfrac{7}{25}\times100=7\times4=28\%}$

% of Nickel = $\sf{\dfrac{5}{25}\times100=5\times4=20\%}$

Therefore, the total percent adds up to 100%.

So,

% of Copper = 52%

% of Zinc = 28%

% of Nickel = 20%

Hope it helps u

Have a great day ahead

Annyeong