Question

an alloy contains 32% copper, 40% zinc and the rest nickle. find the grams the quantity of each of the contents in 1 kg alloy​

Answer 1

32/100*1000 then 40/100*1000gm then add both values

Answer 2

Step-by-step explanation:-

$solution - \: total \: quantity \: of \: alloy \: = \:1kg \: = 1000g$

$\: \: \: \: \: \: \: \: quantity \: of \: copper \: in \: it \: = \: 32\% \: of \: 1000g$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: (1000 \times \frac{32}{100} ) \: g \: = \: 320 \: g$

$quantity \: of \: zinc \: in \: it = \: 40\% \: of \: 1000g$

$\: \: \: \: \: \: \: \: \: = (1000\times \frac{40}{100} g \: = \: 400g$

$∴ \: the \: quantity \: of \: nickle \: in \: it \: =1000 - (300 + 400)g$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = (1000 - 720)g = 280g$

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