Question

An alloy contains Copper and Zinc in the ratio 7 :3. If it contains 12.6 gram of copper, how much does this alloy weigh?

Answer 1

Let's assume that the alloy can be separated into 10 parts, where 7 parts are copper and 3 parts are zinc.

In fraction form, the components can be written as:

Copper = 7/10

Zinc = 3/10

To find the total mass of the alloy, let it be x and solve as below:

7/10 × x = 12.6

x = 12.6 ÷ 7/10

x = 18

Therefore, the alloy has a mass of 18 grams.

Answer 2

Answer:

$\boxed{\mathbf{\huge{18\:grams}}}$

Step-by-step explanation:

Alloy Contains

Copper And Zinc In Ratio=7:3

Copper Weight in Alloy=12.6 gram

Let Weight of Copper=7x

Let Weight of Zinc=3x

Total Weight of Alloy

=Weight of Copper +Weight of Zinc

=7x+3x

=10x

Weight of Alloy=10x

And Weight of Copper=7x=12.6 gram

Weight of Zinc=3x

So

Weight of (Copper +Zinc)=Weight of Alloy

7x+3x=10x

12.6+3x=10x

12.6=10x-3x

12.6=7x

x=12.6/7

x=1.8

Value of X=1.8

Weight of Zinc=3x

=3×1.8

=5.4 grams

Weight of Alloy =12.6+5.4=18 grams

or 10x=10×1.8=18 grams