Question

An alloy contains the copper and aluminum in the ratio of 7:4. While making the weapons from this alloy, 12% of the alloy got destroyed. If there is 12 kg of aluminum in the weapon, then weight of the alloy required is :
A.14.4 kg
B.37.5 kg
C.40 kg
D.48 kg

Answer 1

_______✨ HEY MATE ✨______

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SOLUTION :-
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Copper : Aluminum = 7 : 4.
Let Copper and Aluminum in the weapon be 7x and 4x respectively.
Given,
Aluminum in weapon = 12 kg
So,
→ 4x = 12.
→ x = 3
Copper = 7x = 7 * 3 = 21 Kg.
Total alloy in the weapon = 12 + 21 = 33 kg
But 12% alloy get destroyed in making the weapon, i.e. 88% alloy is used in the weapon, so, 
→ 88 % alloy = 33 kg
→ 100 % alloy = 37.5 kg.

So , Option (B) is the right answer ✔️

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Answer 2

I think answer is B.