Question

An alloy is made by mixing metal A with metal B. Originally metal A forms FCC lattice structure. When metal B is added, alternate corners and alternate face centres are replaced by metal B. If the empirical formula of the alloy is AxBy then x + y​

Answer 1

14 (fourteen)

Explanation:

no. of Fcc corner atoms

Answer 2

Answer:

Explanation:

Definition of Alloy:

Alloys can either be solid solutions of metallic elements in which all the individual grains/crystals of the metals are of the same composition, or they can be mixtures of metallic phases featuring at least two different solutions, resulting in microstructures containing different types of crystals inside the alloy.

Alloys can either be mixtures of metallic phases with at least two different solutions, producing microstructures with different types of crystals inside the alloy, or they can be solid solutions of metallic elements in which all the individual grains or crystals of the metals are of the same composition.

We have $8$ corners and $6$ faces

When metal $A$ occupy FCC it has atoms at corner and face center when $B$ is added

$A$ at corner $= 4$

$A$ at face center $= 3$

∴ Atom of $A$ per unit cell $= 4*1/8 + 3*1/2 = 2$

  Atom of $B$ per unit cell $= 2$

Empirical formula $= A2B2 = A1B1$

$x = 1 and y = 1$

$x+y = 1+1 = 2$

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