Chemistry, asked by Linda7879, 1 year ago

An alloy of copper and aluminum has 40% copper. An alloy of copper and zinc has copper and zinc in the ratio 2: 7. These two alloys are mixed in such a way that in the overall alloy, there is more aluminum than zinc, and copper constitutes x% of this alloy. What is the range of values x can take?

Answers

Answered by vermaarun927
0

Answer:

There is no way that you will have a r and a us back to you in

Answered by AneesKakar
2

Answer:

Between 32.25 and 40%.

Explanation:

For the first case the ratio of copper to alloy will be 2:3. Since, from the question we know that 40% of copper and 60% of aluminium is present. The separation will be 2x and 3x

Then, the ratio of copper to zinc is 2:7. So, the separation will be 2y and 7y. So, the total percentage of copper from the above deduction will be after putting x=7 and y=3. So, the copper will be 2*7 + 2*3=20. While the total is 35+27. So, the ratio will be 20/62*100= 32.25%.

Again, when the aluminium is maximum then putting x=1 and y=0. We will get the percentage of copper 2/5*100=40% . Hence, we see that the percentage of copper will lie between 32.25 and 40 percent.

Similar questions