Question

an Alpha particle and a Proton enters a region of uniform magnetic field which is perpendicular to the direction of motion the ratio of respective radius of the circle described by them if they have same Momentum is​

Answer 1

Answer:

We know that the formulae of the radius is r=mv/qB hence we know that the mass of the alpha particle is 4 times the mass of proton particle and the charge of the alpha particle is 2 times the charge of proton.

Hence the ratio of the proton radius to the alpha radius will be:-

rp/ra = mp/ma*qa/qp.

Hence now purring the values we will get that rp/ra = 1/4 * 2/1 whihc will be 1:2.

Answer 2

Explanation:

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