Question

An alpha particle is accelerated through a potential difference of 10 kv. its gain in kinetic energy is

Answer 1

well u asked question 2 times

Answer 2

Answer:

The kinetic energy is $1.6\times10^{-21}\ J$

Explanation:

Given that,

Potential difference = 10 kv

We need to calculate the kinetic energy

$K.E = qv$

Where, q = charge

v = potential difference

$K.E=1.6\times10^{-19}\times10\times10^{-3}\ J$

$K.E=1.6\times10^{-21}\ J$

Hence, The kinetic energy is $1.6\times10^{-21}\ J$