Question

An alpha particle is accelerated through a potential difference of 10⁶ volt. Its kinetic energy will be(a) 1 MeV(b) 2 MeV(c) 4 MeV(d) 8 MeV

Answer 1

4 Mev should be the answer

Answer 2

Answer:

Explanation:

Potential Difference = P.D = V = 10⁶ volt = 1000000v

Charge on Alpha particle q = 2e = 2 x 1.6 x 10^-19

Therefore, the kinetic energy,

K.E = Charge times Potential difference

= q V = 2e x V

=( 2 x 1.6 x 10^-19 ) x 1000000

= 3.2 x 10^-19 x 10^6

= 3.2 x 10^(-19+6)

= 3.2 x 10^ -13 Joules

= -13 Joules

The charge of a particle will be twice than an electron hence, the charge will be doubled