Question

An Alpha Particle Is accelerated Through potential difference of 25000 volt What will be the increase in its energy in joule

Answer 1

Howdy!!

your answer is ----

Given, V = 25000volt
we know that
charge of an alpha particle is
$6.644 \times {10}^{ - 27}$
now,

V= W/Q

= >W = V × Q

=> W =
$25000 \times 6.644 \times {10}^{ - 27} = 166100 \times {10}^{ - 27} \\ = 1.661 \times {10}^{ - 22} joule$



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