Question

An alpha particle is placed in an charged field at a point having electric potential 5v.Find its potential energy

Answer 1

Hi Mate!  

U=qv.
Thus U= 2x1.6x10-19x5=1.6x10-18J


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Answer 2

Answer:

Potential energy, U = 1.6 × 10⁻¹⁸ J

Explanation:

Given that an alpha particle is placed in an charged field at a point having electric potential 5 V. The relation between the electric potential and potential energy is given by the following relation :

$U=qV$

Where

U is the potential energy

q is the charge of alpha particle, $q_\alpha=2e=3.2\times 10^{-19}\ C$

So,  $U=3.2\times 10^{-19}\times 5$

$U=1.6\times 10^{-18}\ J$

Hence, this is the required solution.