Question

An alpha particle is situated in an electric field 4*10to the power 5 .force experiance by it is

Answer 1

Answer:

Force experienced = 1.28×10⁻¹³ N

Explanation:

We know that,

F = qE  and

q = ne

Given that,

E = 4×10⁵

n = 2 (Since it is an alpha particle)

e = 1.6×10⁻¹⁹ C

Therefore,

q = 2×1.6×10⁻¹⁹

q = 3.2×10⁻¹⁹

Hence, substituting all the values in

F = qE

F = 3.2×10⁻¹⁹×4×10⁵

F = 12.8×10⁻¹⁴

F = 1.28×10⁻¹³ N