An alternating voltage E (in volts) = 200 √2 sin 100 t is
connected to one micro farad capacitor through an a.c.
ammeter. The reading of the ammeter shall be
(a) 100 mA (b) 20 mA (c) 40 mA (d) 80 mA
Answers
Answered by
0
Explanation:
I think option A is the answer
Answered by
3
Answer:
Answer : option (b)
explanation : equation of alternating voltage , E = 200√2sin(100t)
compare this equation with
so, volts
= 100 rad/s
now,
= 200√2/√2 = 200 volts .
given, capacitance of capacitor, C = 10^-6F
so, reactance of capacitor,
=
=10⁴
so, the reading of Ammeter ,
= 200/10⁴ A = 20 × 10^-3 A = 20mA
hence, option (b) is correct.
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