Physics, asked by vaishnaviwalunj29, 7 months ago

an alternating voltage given by e=65sin(314t) is connected across a pure resistor of 100 ohm. find the frequency of the source

Answers

Answered by awanfateh13

0

Answer:

50Hz

Explanation:

Given Data:

V=65sin(314t)

R=100Ohm

Find Out:

frequency=f=?

Solution:

V=Vosinwt

V=65sin(314t)

$V_{0}$ =65volts

W=314

W=2πf=>314=2πf

f=314/2 ×3.14

f=50Hz

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