an altitude of a triangle is five third the length of its corresponding base. if the altitude were increased by 4cm and the base be decreased by 2cm the area of the triangle would remain the same. find the base and the altitude of the triangle
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let the base be x
therefore altitude=5x/3
as per ques.,
base=x-2
altitude=5x/3+4
area of ∆=1/2×base×hieght
(1/2)×(x)×(5x/3)=(1/2)×(x-2)×(5x/3+4)...........
Now we can solve it withe the method of transposition.
therefore altitude=5x/3
as per ques.,
base=x-2
altitude=5x/3+4
area of ∆=1/2×base×hieght
(1/2)×(x)×(5x/3)=(1/2)×(x-2)×(5x/3+4)...........
Now we can solve it withe the method of transposition.
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