An altitude of a triangle is five-thirds the length of its corresponding base. If the altitude be increased by 4cm and the base decreased by 2cm, the area of the triangle remains the same.
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h = 5 b / 3
1/2 * (h +4)*(b - 2) = 1/2* h b
So 4 b - 2 h = 8
2 b - h = 4
2 b - 5b/3= 4
b = 12 cm
h = 20 cm
1/2 * (h +4)*(b - 2) = 1/2* h b
So 4 b - 2 h = 8
2 b - h = 4
2 b - 5b/3= 4
b = 12 cm
h = 20 cm
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