An altitutde of a triangle is five-thirds the length of its corresponding base. If the altitude were increased by 4 cm and the base be decreased by 2 cm, the area of the triangle would remain the same. Find the base and the altitude of the triangle.
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Step-by-step explanation:
if h cm is the altitude,and x cm is it's corresponding base then h=5x/3
if height is (h+4),and base is (x-2)
then area 1/2.(h+4).(x-2)
so,1/2.x.h=1/2.(h+4).(x-2)
x.h=(h+4).(x-2)
x.5x/3=(5x/3 +4)(x-2)
5x^2/3=(5x+12)(x-2)/3
5x^2=5x^2+12x-10x-24
2x-24=0
x=24/2=12
h=12×5/3=20
so base is 12 cm and height is 20cm
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