Math, asked by niranjan47, 1 year ago

An amoeba doubles every hours. How many amoebas would be at the end of 7 hours, if there was 1 amoeba in the beginning? ​


Parthdhami: 128

Answers

Answered by LostMagician
5

at 1st hr 1 amoeba divide in 2

in the next hr it's becomes 4 hence eventually It becomes 128 amoebas at the end


LostMagician: My name is Shubhsm
LostMagician: Shubham*
LostMagician: lol
darshan200585: hi
LostMagician: helllo
darshan200585: hello
Hermione1402: bye
Hermione1402: :(
LostMagician: byeeee
Answered by darshan200585
7

an amoeba doubles every hours . how many amoebas would be at the end of 7 hours ,if there was 1 8n beginning?

answer is 128

Explanation

it was 1 in beginning

I +1in one hour =2

2+2in 2 hours =4

4+4in 3hours =8

8+8in 4hours =16

16+16in 5 hours =32

32+32in 6 hours=64

64+64 in 7 hours =128

There fore the answer is 128

hope it helps you.

Similar questions