Question

A body constrained to move in the y direction is subjected by f=(_2i+15j+6k)n.what is the work done by this force in moving a distance 10m along the y- axis

Answer 1

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Answer 2

Answer:

Explanation: ( WORKDONE = FORCE.DISPLACEMENT)

(-2î + 15j + 6k)N . 10j

And the Answer is 150J because all the value of distance is 0î and 0k which when we multiple with -2î and 6k is 0 (ZERO)

THEREFORE,ONLY WE HAVE MAGNITUDE OF Y AXIS THAT'S WHEN WE MULTIPLE THE ANSWER COME 15.10 = 150J

HOPE IT WILL BE CLEAR........