Chemistry, asked by ritu9021, 5 months ago

an amount of 1.00 g of gaseous compound of boron and hydrogen occupies 0.820 liter at 1.00 atm and 3°C. the compound is(R= 0.0820 liter atm/mol.K at at. H =1.0 B=10.8)

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Answered by Ansh0725

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An amount of 1.00 g of a gaseous compound of boron and hydrogen occupies 0.820 L at 1.00 atm and at 3°C. The compound is : (R = 0.0820 L atm mole-1 K-1, at.

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an amount of 1.00 g of gaseous compound of boron and hydrogen occupies 0.820 liter at 1.00 atm and 3°C. the compound is(R= 0.0820 liter atm/mol.K at at. H =1.0 B=10.8)​

Answers

an amount of 1.00 g of gaseous compound of boron and hydrogen occupies 0.820 liter at 1.00 atm and 3°C. the compound is(R= 0.0820 liter atm/mol.K at at. H =1.0 B=10.8)