Question

An amount of 600 a deposited in
A bank geelded in interest of
240. How much money
should be deposited to
earn an interest of 800​

Answer 1

Answer:

p=600

si=240

t= 1y

$r = \frac{si \times 100}{p \times t} \\ = \frac{240 \times 100}{600 \times 1} \\ = 40\% \\ si = 800 \\ p = \frac{si \times 100}{t \times r} \\ = \frac{800 \times 100}{1 \times 40} \\ = 2000$

Therefore

2000 must be deposited to get 800 as si