an amount of rs 6600 is divided among three partners X,Y and Z. , so that X receives 3/7th of what Y and Z received together and Y receives 13/20th of what X and Z RECIEVED together , Find the share of each partner
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Given:
an amount of rs 6600 is divided among three partners X,Y and Z.
To find:
The share of each partner
Solution:
As we have given the condition that can be expressed as:
X/Y+Z = 3/7
- X+Y+Z = 3+7 = 10
Y/X+Z = 13/20
- X+Y+Z = 13+20 = 33
but the sum of the share must be same so make it same
(X/Y+Z = 3/7)33
- X/Y+Z = 99/231
- X+Y+Z = 99+231 = 330
(Y/X+Z = 13/20)10
- Y/X+Z = 130/200
- X+Y+Z = 130+200 = 330
Shares of the
- X = 99
- Y = 130
- Z = 101
330 ------- rs 6600
1 ----------- rs 20
So the shares of the partners are given by:
- X = 99×20 = 1980
- Y = 130×20 = 2600
- Z = 101×20 = 2020
The share of each partner are rs 1980, rs2600, and rs2020
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