An amphoteric oxide ‘X’ reacts with aqueous NaOH
to form sodium aluminate. Identify the product when
‘X’ reacts with hydrochloric acid
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amphoteric oxide X is Al2O3 .
Al2O3 +6 HCl gives 2AlCl3 + 3H20
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Answer:
1. X = Aluminium (Al) .
2.The product when Aluminium reacts with hydrochloric acid is 2AlCl3(aq) + 3H2(g).
Explanation:
i) 2X + 2Na(OH)2------→ 2NaAlO2 + 2H2.
ii) 2Al(s) + 6HCl(aq) -----→ 2AlCl3(aq) + 3H2(g).
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