Question

an angle of 15degree to rhe horizontal with an initial velocity to hit a target 300m away. calculate initial velocity and maximum height

Answer 1

Answer:

Explanation:

Given -

Range , R = 300 m

angle of projection , θ = 15°

To Find -

Initial velocity = V

maximum height = H

Process -

As per formula

Range,

R = (V² sin 2θ) / g

=> 300 = V² sin 2(15°) / g

=> 300 = V² sin 30° / 10

=> 3000 = V² × 1/2

=> 6000 = V²

=> V² = 6000

=> V = 77.46 m/s

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And,

Height,

H = (V² sin²θ) / 2g

= ( 6000 × sin²15° ) / ( 2 × 10 )

= 6000 × 0.067 / 20

= 300 × 0.067

= 20.07 m

______________

Hence, the initial velocity is 77.46 m/s and the maximum height reached is 20.07 m .