An angle of a parallelogram is 40° more than its adjacent angle. Find the measures of all its angles.
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Let one angle =X+40
Let the another angle =X
In llgm opposite angle are equal
Angle sum property of a llgm =360
X+40+X+40+X+X=360
4X+80=360
4X=360-80
X=280/4
X=70
Angles are 70°,70°,110°,110°
Let the another angle =X
In llgm opposite angle are equal
Angle sum property of a llgm =360
X+40+X+40+X+X=360
4X+80=360
4X=360-80
X=280/4
X=70
Angles are 70°,70°,110°,110°
Ashishchoudhary999:
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Answered by
5
Given - Angle's relation with other angles
Find - Measure of all angles
Solution - Let one angle of parallelogram be x. So, the two adjacent angles will be (x + 40). The remaining angle will be x.
Sum of the interior angles of parallelogram is 360°.
x + x + 40 + x + x + 40 = 360
Performing addition
4x + 80 = 360
4x = 360 - 80
Performing substraction
4x = 280
x = 280/4
Performing division
x = 70
The measure of two angles = 70°
Measure of other two angles = x + 40
Measure of other two angles = 70 + 40
Measure of other two angles = 110°
Hence, the four angles of parallelogram are 70°, 70°, 110° and 11p0°.
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