an angle of a parallelogram is of measure 70 degree find the measure of remaining angles of parallelogram
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70 ,110,110because the sum of all angles of a quad. is 360 70(given)
70+110+110+70=360
70+110+110+70=360
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Opposite angles of parallelogram are equal.
Let angle A is 70 = angle c is 70
Let angle D be x = angle B is x
(Opposite side of the parallelogram)
Therefore angles
A+B+C+D =360
140+2x= 360
2x= 220
X= 110
angles
A=70
B=110
C=70
D=110
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