Question

if sec theta + tan theta = p then what is the value of sec theta - tan theta

Answer 1

Hi ,

Here I am using A instead of theta .

It is given that ,

Sec A + tan A = p ---( 1 )

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By Trigonometric identity :

Sec²A - tan² A = 1

Algebraic identity :

a² - b² = ( a + b )( a - b )

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Sec² A - tan² A = 1

( SecA + tan A )( secA - tanA ) = 1

p × ( sec A - tan A ) = 1 [ from ( 1 ) ]

Sec A - tan A = 1/p

I hope this helps you.

Answer 2

sec theta - tan theta =1/p
proof ..
sec^2@ - tan^2@ = 1 so
(sec@+tan@)(sec@-tan@) = 1
sub p in sec@+tan@ as it is given then
sec@-tan@=1/p
hope u like it